Physics
NULL
Medium
Question
A rubber cord of cross-sectional area 2cm2 has a length of 1m. When a tensile force of 10N is applied the length of the cord increases by 1cm. What is the youngs modulus of rubber ?
A
2 × 10⁸ N m⁻²
B
5 × 10⁶ N m⁻²
✓ Official correct answer
C
0.5 × 10⁻⁶ N m⁻²
D
0.2 × 10⁻⁶ N m⁻²
Community credibility
Registered members can vote for the answer they believe is correct today and explain why. If the facts change after an election or news event, suggest a new option so others can vote it up.
A
2 × 10⁸ N m⁻²
No member explanations yet for this option.
B
5 × 10⁶ N m⁻²
No member explanations yet for this option.
C
0.5 × 10⁻⁶ N m⁻²
No member explanations yet for this option.
D
0.2 × 10⁻⁶ N m⁻²
No member explanations yet for this option.
Explanation
Young's modulus Y = FL/(AΔL) = (10N x 1m)/(2x10^-4 m^2 x 0.01m) = 10/(2x10^-6) = 5x10^6 N/m^2.
Related Questions
Q
The waves which are used for line of sight (LOS) communication are called:
Medium
· Physics
Q
A potential difference is applied across the ends of a wire. If the potential di...
Medium
· Physics
Q
Relation between linear velocity and angular velocity:
Medium
· Physics
Q
If the axis of rotation passes through the body and the body moves around itself...
Medium
· Physics