TayariHub
Mathematics NULL Medium
Question

A vendor has 80 L of Maaza, 144 L of Pepsi and 368 L of Sprite to pack in equal cans without mixing drinks. What is the least number of cans required?

A
35
B
37
✓ Official correct answer
C
42
D
30

Community credibility

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A
35
Official option

No member explanations yet for this option.

B
37
Official option

No member explanations yet for this option.

C
42
Official option

No member explanations yet for this option.

D
30
Official option

No member explanations yet for this option.

Explanation

Largest can size = gcd(80,144,368) = 16 L. Cans = 80/16 + 144/16 + 368/16 = 37.

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